LeetCode-235
Links:https://leetcode.com/problems/lowest-common-ancestor-of-a-binary-search-tree/
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
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_______6______ / \ ___2__ ___8__ / \ / \ 0 _4 7 9 / \ 3 5 |
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
题意:找到最近共同祖先节点
思路:根据BST的特性,如果pq的值都大于root,到right子树查找,如果都小于,到left子树查询,否则返回root…
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/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) { if(root->val > p->val && root->val>q->val) { return lowestCommonAncestor(root->left, p, q); } else if(root->val < p->val && root->val<q->val) { return lowestCommonAncestor(root->right, p, q); } else{ return root; } } }; |
【LeetCode】235. Lowest Common Ancestor of a Binary Search Tree